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Finding this function?
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\[\frac{ f(a+h)-f(a) }{ h }\]
If H is \[\neq0\]
it goes with the main problem of \[f(x)=6x-6\]
\[\frac{ 6a+6h-12+6a-6 }{ h }\] is what I get When cominging everything I get \[\frac{ 6(2a+h-3) }{ h }\] but the homework claims it is wrong any help?
You weren't careful with parentheses and minus signs.
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\[\Large \frac{ 6(a+h) - 6 - (6a-6) }{ h }\]
THEN 6 IS THE ANSWER
YEP
Ah ok I was inputting the answers I had previously is why I mess up the format probably. What about this: \[f(x)=x^2-x+14\] \[f(-a)\] I get \[-a^2+a+14\] and get that wrong?
(-a)^2 does not equal -a^2
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just a? or what am I missing?
What is (-2)^2?
Is it 4 or -4?
ah yes becuase -*- thanks
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