Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

Finding this function?

OpenStudy (anonymous):

\[\frac{ f(a+h)-f(a) }{ h }\]

OpenStudy (anonymous):

If H is \[\neq0\]

OpenStudy (anonymous):

it goes with the main problem of \[f(x)=6x-6\]

OpenStudy (anonymous):

\[\frac{ 6a+6h-12+6a-6 }{ h }\] is what I get When cominging everything I get \[\frac{ 6(2a+h-3) }{ h }\] but the homework claims it is wrong any help?

OpenStudy (agent0smith):

You weren't careful with parentheses and minus signs.

OpenStudy (agent0smith):

\[\Large \frac{ 6(a+h) - 6 - (6a-6) }{ h }\]

OpenStudy (anonymous):

THEN 6 IS THE ANSWER

OpenStudy (agent0smith):

YEP

OpenStudy (anonymous):

Ah ok I was inputting the answers I had previously is why I mess up the format probably. What about this: \[f(x)=x^2-x+14\] \[f(-a)\] I get \[-a^2+a+14\] and get that wrong?

OpenStudy (agent0smith):

(-a)^2 does not equal -a^2

OpenStudy (anonymous):

just a? or what am I missing?

OpenStudy (agent0smith):

What is (-2)^2?

OpenStudy (agent0smith):

Is it 4 or -4?

OpenStudy (anonymous):

ah yes becuase -*- thanks

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!