Question

integral random question,


Can I split this integral into one integral of "2" minus another integral of the "fraction" ?

Answer 1

Ops forgot to mention the integral : http://screencast.com/t/sFjYCiQ4R

Answer 2

There it is* ^

Answer 3

yes, you can`

Answer 4

ok sec

Answer 5

so my answer to this integral is 2x - 16xln(x^2 + 4) + c . Is it correct ?

Answer 6

nopes.

Answer 7

\(\Large \int \dfrac{1}{x^2+a^2}dx=\dfrac{1}{a}\tan^{-1}({\dfrac{x}{a}})\)

Answer 8

here a^2= 4

Answer 9

yup.

Answer 10

\[\LARGE 2 \int\limits dx-8 \int\limits \frac{dx}{x^2+4}\]

Answer 11

I know this way at @hartnn but I just tried to do it another way without involving reverse functions, you understand what I was trying to do ?

Answer 12

no way to do it without tan inverse.

Answer 13

to involve ln(x^2+4), there should have been 2x in the numerator, but there isn't.

Answer 14

I see, thanks!

Answer 15

welcome ^_^