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f(x) = x-3/8; g(x) = 8x + 3, find g(f(x)).
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\(g(f(x)) = 8\left(\dfrac{x - 3}{8}\right) + 3 = x - 3 + 3 = x\)
Why did you just multiply it by 8 instead of the entire equation 8x+3?
You mean why did I put \(\dfrac{x - 3}{8}\) in place of \(x\) in \(8x + 3\) ?
The 8 cancels it out .. 8(x-3)/8 you can cancel the two of them out.
Ohh I see what you did! I thought it was supposed to be the opposite way. Thanks!
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It's fine. I still understand what you were trying to do. Thanks again! :)
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