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help understand answer see in comment
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f(g(1/2) \[f(x)=\sqrt[3]{x+1}\] \[g(x)=4x ^{2}-x\] found g(1/2) is still 1/2 to plug back in got \[\sqrt[3]{\frac{ 1 }{ 2 }}+1\] which is then \[\sqrt[3]{\frac{ 3 }{ 2 }}\] howerver the book says \[\frac{ \sqrt[3]{12} }{ 2 }\]
|dw:1381716367320:dw| That is your answer, and it is invalid you have to remove a radical from the denominator. More help?
Cneck your work again, are you sure your answer is right? I don't... esp that the book says...
Hold, on actually maybe!
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Do you see my fraction. Multiply the top and bottom by |dw:1381716580989:dw|
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