Question

a circle has the following equation 2(x-3)^2+2y^2=8. find the center (h,k) and radius

Answer 1

Find the formula for h,k

Answer 2

First divide both sides by 2

Answer 3

You now have (x - 3)^2 + y^2 = 4

Answer 4

Center is (h,k) where the equation of the circle is (x - h)^2 + (y-k)^2 = r^2, and r = radius of the circle

Answer 5

So, what is the center and radius of the circle?

Answer 6

formula for h,k is (x-h)^2+(y-k)^2=r2

Answer 7

idk im stuck