Question

what is the integral of (x+3)/(x^2+1)

Answer 1

Hint: break up the integral as x/(x^2 + 1) + 3/(x^2 + 1)

The first integral is easy with u = x^2 + 1

Second integral involves arc tan u

Answer 2

I got the first integral. I guess I am confused about the 3 in the second

Answer 3

The second integral is 3 times the integral of 1/(x^2 + 1) = Arc tan (x), so the second integral is 3 Arc tan (x).

Answer 4

The integral of dx/(1+x^2) = Arc tan (x)...thats one of them you should know

Answer 5

The first integral is 1/2 ln(x^2 + 1)

Answer 6

Okay that's what I got! Thanks so much

Answer 7

Welcome.

Answer 8

Your final answer should be: (1/2) ln (x^2 + 1) + 3 arc tan (x) + C