The volume in cubic feet of a workshop's storage chest can be expressed as the product of its three dimensions: V(x)=x^(3)-4x^(2)-x+4. The depth is x+1. a. Find linear expressions with integer coefficients for the other dimensions. d=(x+1) b. If the depth of the chest is 7 feet, what are the other dimensions? length=8 (I have included the parts that I got correct and received half-credit for.)
hi, yeah, sorry. Try this to find a (x+1)(Ax^2+Bx+C) = x^3 - 4x^2-x+4
does that make sense?
I see it, but i don't understand how that would help me solve this problem.
well I'd use a little polynomial division or synthetic division to get the base area... |dw:1381731246738:dw| so base area times height is \[V= (x +1)(x^2 -5x + 4)\] factor the quadratic for the dimensions of the base...
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