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find an equation for the line through (-7,-6) and perpendicular to y=-3/2x+1
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Hint: The the other line you're looking for is perpendicular, then the slope will be \(\dfrac{2}{3}\)
The slopes should be negative reciprocals!
If two lines are perpendicular to each other then the product of their slopes will be -1.
\[-\frac{3}{2} \times \frac{2}{3} =- 1\]
thus the slopes are negative reciprocals hahaha
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y=mx+b the slope of the 2nd equation is - 3/2
I think the slope of the second equation is 2/3
Yup ! then follow this equation ---> y-y1=m(x-x1) to get the next equation x1 and y1 are the given points and m=2/3 since they are negative reciprocals
That's prolly it. you'll get it after you finalize that equation
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