Use logarithms to solve the equation.

e-3x = 0.01

Question

Use logarithms to solve the equation.

e-3x = 0.01

anonymous · Answer

I need help on the same one

anonymous · Answer

*e^-3x

wolfe8 · Answer

When you have e, you get rid of the e with log. So what you do is you log both sides. Tell me how that would look like and I will guide you from there.

anonymous · Answer

so you would get log(e^-3x)? Or would it be log(subscript)e -3x?

anonymous · Answer

=log 0.01

wolfe8 · Answer

The first one. It would be log log(e^-3x)
Now, then you have log multiplied with e, they cancel each other out, or the product becomes 1. And what you have left will be the superscript of the e.

wolfe8 · Answer

Can you give me a min to check first?

anonymous · Answer

and then log0.01=-2?
so how would you put this all together?

anonymous · Answer

Oh, yep, of course!

wolfe8 · Answer

Ugh I am such a klutz lately. I'm sorry I missed an important detail to the question. Since the power is negative, you can rewrite it as $$\frac{ x }{ e ^{3} }=0.01$$ Now you can solve it like a fractional equation. Can you do that?

anonymous · Answer

Yeah! Thank you!

wolfe8 · Answer

You're welcome. Sorry again I made that stupid mistake. I made it complicated and I think wrong too. My mind is a mess atm. Good luck and I'll try to help you with any more questions.

anonymous · Answer

Thank you very much for your help! And don't worry about it; after all, everyone has bad days! (:

wolfe8 · Answer

@googlesun does this help?