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derivative of sin^2x
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you have to use the power rule and chain rule
sin^2x=(1-cos2x)/2
actually it should be 2sinxcosx
2sinxcosx=sin2x but in this case, \[\sin ^{2}x\]
sin2x would be 2cos2x
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no, sin2x=2sinxcosx
http://www.derivative-calculator.net/ you go ahead and plug those in. Just to show you. you're not applying chain rule correctly.
oh, big misunderstanding! I mean sin2x=2sinxcosx not derivative of sin2x equals 2sinxcosx
ok
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