Question

Is this a proper way to approach this Trig Identity Exp. ? Please help and thank you.
sin(x)tan(x)/cos(x)
=sin(x)*(sin(x)/cos(x))/cos(x)
=sin^2(x)

Answer 1

Nope

Answer 2

I think it'd be like:
sin(x)tan(x)/cos(x)
= sin(x)(sin(x)/cos(x))/cos(x)
so then you'd multiply top and bottom by cos(x)
and then you get:
sin^2(x) / cos^2(x)
which is essentially
(sin(x) / cos(x)) ^ 2, or tan^2(x)

Answer 3

Oooohhh I see where I went wrong ! Thank you so much @isoganaide

Answer 4

Ah thanks @abhilashkusam!