Algebra II. Equations with Paretheses.
A) 12(x -6) = 2(x - 9)

B) 4(7 - 3x) = 7(4 - 2x)

C) 7(x - 2) + 3(x + 2) = 5(x - 6)

D) 4(2x -3) + 8(x - 4) = 2(2x + 6)

E) 4(7x - 1) = 3(2x + 1) - 4(x + 6)

F) 12(2x - 8) = 4(5 - 2x) + 3(7 - 3x)

G) 3(x - 2) + 4(2x - 6) = 6(x - 4) + 8(2x + 1)

Any help you could provide to giving or helping me find these answers would be lovely! :)

Question

Algebra II. Equations with Paretheses.
A)  12(x -6) = 2(x - 9)

B)  4(7 - 3x) = 7(4 - 2x)

C)  7(x - 2) + 3(x + 2) = 5(x - 6)

D)  4(2x -3) + 8(x - 4) = 2(2x + 6)

E)  4(7x - 1) = 3(2x + 1) - 4(x + 6)

F)  12(2x - 8) = 4(5 - 2x) + 3(7 - 3x)

G)  3(x - 2) + 4(2x - 6) = 6(x - 4) + 8(2x + 1)

Any help you could provide to giving or helping me find these answers would be lovely! :)

anonymous · Answer

12x-72=2x-18
10x=90
x=9
Just multipy each one out and then add or subtract like terms to get x on one side and constants on the other then solve for x

anonymous · Answer

This problem look more like an Algebra I problem.

I will do (E)..then you work on the rest. All same type.

4(7x-1) = 3(2x+1) - 4(x+6)

Use Distributive Law, to get rid of parenthesis,

28x - 4 = 6x + 3 - 4x - 24
28x - 4 = 2x - 21
26x =-17
x = -17/26

anonymous · Answer

28x - 4 = 6x + 3 - 4x - 24
is x=17/26