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Mathematics 19 Online
OpenStudy (otonogold):

Multiple Choice :) A candy store makes 13-pound mixture of gummy candy, jelly beans, and hard candy. The cost of gummy candy is $1.00 per pound, jelly beans cost $2.00 per pound, and hard candy cost $2.00 per pound. The mixture calls for three times as many gummy candy pieces as jelly beans. The total cost of mixture is $20.00. How much of each ingredient did the store use? A: 8 lbs. gummy candy 2 lbs. jelly beans 3 lbs. hard candy B: 3 lbs. gummy candy 6 lbs. jelly beans 4 lbs hard candy C: 6 lbs gummy candy 2 lbs. jelly beans 5 lbs. hard candy

OpenStudy (otonogold):

D: 8 lbs. gummy candy 3 lbs. jelly beans 2 lbs. hard candy

OpenStudy (otonogold):

I think it might be C Im not sure.

OpenStudy (anonymous):

its not c

OpenStudy (anonymous):

wait im confused

OpenStudy (otonogold):

It might be A or D.. I don't know, Im confused too.

OpenStudy (anonymous):

hmmmmm

OpenStudy (agent0smith):

Work it out from this: The total cost of mixture is $20.00 gummy candy is $1.00 per pound, jelly beans $2.00 per pound, hard candy $2.00 per pound and this might even be all you need: three times as many gummy candy pieces as jelly beans which option has 3x the number of gummy candy, as jelly beans?

OpenStudy (agent0smith):

A: 8 lbs. gummy candy 2 lbs. jelly beans 3 lbs. hard candy B: 3 lbs. gummy candy 6 lbs. jelly beans 4 lbs hard candy C: 6 lbs gummy candy 2 lbs. jelly beans 5 lbs. hard candy D: 8 lbs. gummy candy 3 lbs. jelly beans 2 lbs. hard candy Only one option has three times as much gummy as jelly beans.

OpenStudy (otonogold):

B?

OpenStudy (otonogold):

@agent0smith

OpenStudy (otonogold):

?

OpenStudy (agent0smith):

Not B. The amount of gummy candy has to be triple the amount of jelly beans.

OpenStudy (otonogold):

so it was C I was right the first time?

OpenStudy (otonogold):

@agent0smith ?

OpenStudy (otonogold):

?

OpenStudy (agent0smith):

Yes but you weren't sure the first time, now you should be sure.

OpenStudy (otonogold):

Thank you for making it clear :)

OpenStudy (agent0smith):

welcome :)

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