Question

The graph of which quadratic equation is shown below?

(picture will be attatched)

y = x^2 + 6x − 5

y = x^2 − 6x − 5

y = −x^2 − 6x − 5

y = −x^2 + 6x − 5

Answer 1

i need help

Answer 2

@Tyler1992

Answer 3

well the vertex of the graph you have given is (3,4) so you need to find the vertex of each of the equations you have given to see which one it is. Your equations are in the form \[y = ax^2 + bx + c\] and the vertex is \[(-\frac{b}{2a}, \frac{4ac - b^2}{4a})\]

Answer 4

all you have to do is plug in numbers and compare

Answer 5

plug them in where?

Answer 6

plug the numbers into the vertex equation and see if you get the result (3,4)

Answer 7

i got b as the answer but idk

Answer 8

well lets see

Answer 9

ok

Answer 10

\[-\frac{b}{2a} = - \frac{-6}{2} = 3 \] so far so good\[\frac{4ac - b^2}{4a} = \frac{4(1)(-5) - (-6)^2}{4} = 14\]

Answer 11

not b :/

Answer 12

oh

Answer 13

where do u get 1 from?

Answer 14

coefficient in front of the x is 1

Answer 15

is it + 6x-5?

Answer 16

ohhhhh ok

Answer 17

x^2 i mean

Answer 18

the whole thing is 1

Answer 19

the answer is D