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cos(2a) (picture)
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|dw:1381981406455:dw|
\[\cos \theta = \frac{ adjacent }{ hypotenuse }\]
would I just multiply cos(a) by 2 then?
it says the correct answer is 161/289
Im finding the cos of 16/15?
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Use the formula: cos(2x) = 2cos^2(x) - 1 So find the hypotenuse first. h^2 = 8^2 + 15^2. So h = ?
\[\sqrt{289}\]
Yes and sqrt(289) = 17 Now find cos(a) = adjacent / hypotenuse = 15 / 17 Put it in the equation cos(2a) = 2(cos(a))^2 - 1
Well?
ok i figured it out thank you
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