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Mathematics 16 Online
OpenStudy (anonymous):

cos(2a) (picture)

OpenStudy (anonymous):

|dw:1381981406455:dw|

OpenStudy (anonymous):

\[\cos \theta = \frac{ adjacent }{ hypotenuse }\]

OpenStudy (anonymous):

would I just multiply cos(a) by 2 then?

OpenStudy (anonymous):

it says the correct answer is 161/289

OpenStudy (anonymous):

Im finding the cos of 16/15?

OpenStudy (ranga):

Use the formula: cos(2x) = 2cos^2(x) - 1 So find the hypotenuse first. h^2 = 8^2 + 15^2. So h = ?

OpenStudy (anonymous):

\[\sqrt{289}\]

OpenStudy (ranga):

Yes and sqrt(289) = 17 Now find cos(a) = adjacent / hypotenuse = 15 / 17 Put it in the equation cos(2a) = 2(cos(a))^2 - 1

OpenStudy (ranga):

Well?

OpenStudy (anonymous):

ok i figured it out thank you

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