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Trigonometry Question
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if \[\tan \theta= \frac{ 2ab }{ a^{2}-b ^{2} }\] find cos theta
i got 2ab, although im not sure that is the answer
tan = sin/cos
so cosine is a^2 - b^2
thank you!
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@shamil98 I don't think that is correct. What if sin = (a^2 - b^2)/b then cos = 2a
why divided by b?
im leaning towards the other answer, because i had that first, but just needed to clarify
im just saying that i think that the answer is: cos theta = (sin theta (a^2 - b^2))/2ab
if you are solving for cos that is , @piglet9 , if he just wants to know what cos value is that is different
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im giving the general answer for cos. Your answer could be right but COULD is not good enough in mathematics. It is more likely to be wrong.
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