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Find an equation of the tangent line to the curve y=(e^x)(sinx) at the point (0,0).
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1) find y' 2) find y' at (0,0). This is the slope 3) You have the slope, you have a point (0,0). You can form an equation by point-slope form
ok y'=e^xsinx+e^xcosx
when x=0 y=1
and when y=0 x=some random number
@Callisto
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No.... You need to find the slope of tangent line at (0,0) So, you need to sub (0,0) into y' to get the slope.
how do you plug a point into the equation. if you put in zero then that means you will get zero
Try.
Sorry, plug x=0 into y'
ok i did and got 1
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1 is the slope m. \[y-y_0 = m(x-x_0)\]\((x_0,y_0) = (0,0)\)
fyi, here is a graph
so the equation would be y=x
Yes.
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