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Given f(x) = the quantity of x plus 4, divided by 6, solve for f-1(7).
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\[f(x)=\frac{ x+4 }{ 6 }\]
solve for f^-1(7).
@Euler271 @amistre64 @agent0smith
hello? o.o
@cwrw238
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Can you find the inverse function? solve this for x (rearrange to get x=...) \[\large y=\frac{ x+4 }{ 6 }\]
x(y)=2(3y-2) ?
@helpme1.2 this one.
You didn't need to factor it at all... x = 6y - 4 is fine. Now swap x and y. SO f^-1(x) = 6x - 4
And find r f^-1(7)
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38...?
i'm guessing that's it? xD
if 6*7 - 4 is 38 then yes that's it :P
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