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Evaluate this limit
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\[\huge \lim_{x \to 1}\frac{ x ^{3}-3x ^{2}+3x-1 }{ \tan(x-1) - \sin(x-1) }\]
have you attempted L'Hopital ?
not allowed... and the bottom is still 0 I think.
I trid to use identities at the bottom but. well we had a nice little confusion
i said let u = x-1 but it got confusing to write it in terms of u.
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does the identity tan(x) = sin(2x) / ( cos (2x) + 1) help ?
no. it makes it more tedious to do but good thinking
not sure. if you figure it out without L'Hopital let me know.
wait the top factors to \[(x-1)^{3}\] so now i can write it as u= x-1
\[\lim_{u \to 0} \frac{u^{3}}{tanu - sinu}\]
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it does. but how do you proceed?
are you allowed to use taylor expansions?
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