Write the equation of the tangent line at the points given: ((x^2) + sqrt(x))/(x+1) @ x=0

Question

campbell_st · Answer

what did you get as the 1st derivative..?

when you substitute x = 0 into the equation you get y = 0

so you are going to use the point (0, 0)

anonymous · Answer

I'm not completely sure if I got the dy/dx right, but I got x^2 +2x -x -1 -sqrt(x)/(x+1)^2 (2sqrtx)

campbell_st · Answer

ok... so if that's you derivative substitute x = 0 and this will give the gradient of the tangent at the point... 


then you can use the slope and point (0, 0) to find the equation of the tangent