AWARDING MEDALS! F(x) = (x-1) (x-2) includes 2 real rational solutions because?
when you set x-1 and x-2 to zero and solve for x, actual numbers come up, not an imaginary number. Also, if you graphed it, there are two distinct places where the graph crosses the x-axis, which means it has two zeros.
oh okay! That makes sense. Thank you!
no problem
Can you help with another one please?
sure
G(x) = (x – ^2) (x- ^2) includes 2 real irrational solutions because?
Okay, so does it looks like this \[G(x)=(x^{-2})(x^{-2})\]?
yes :-)
I made these functions so if they don't work with the question, can you please tell me?
Ok, well the thing is x^-2 = 1/x. and when you graph it, it only approaches the x-axis and never touches it. The x-axis is known as an "asymptote" and because it never actually touches the x-axis the zeroes that it has are irrational. Also when you set the equation inside the parentheses to zero, it is impossible to solve for x.
oh okay! That makes sense! thanks soo much!!
no prob
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