Question

At 1 atm, how much energy is required to heat 93.0 g of H2O(s) at –24.0 °C to H2O(g) at 115.0 °C?

Answer 1

you need to use 2 equations, in 5 steps.

(1) \(q=H_{fusion/vap}*m\)
(2) \(q=m*C_p*\Delta T\)



In A, your heating up the ice from -24 to 0 degrees: use equation (2) and the appropriate \(C_P\).

In B, the ice is melting, use equation (1), use appropriate \(H_{fusion}\)

In C, you're heating up the water form 0 to 100 degrees, use equation (2).
Use appropriate \(C_p\).

In D, you're vaporizing/boiling the water, use equation (1), use appropriate \(H_{vap}\).

In E, you're heating up the water vapour/steam, use equation (2), use appropriate \(C_p\).