PRE CALC HOMEWORK HELP!!!

Question

anonymous · Answer

Determine the equations of the symptoms of 
g(x)= 3x^2 -12/(x+4)

dumbcow · Answer

is the equation sick :)

anonymous · Answer

*asymptotes

dumbcow · Answer

that what i thought...now is that all the numerator "3x^2-12" ?

anonymous · Answer

But yea that's all

dumbcow · Answer

vertical asymptote is where bottom = 0
x +4 = 0
x = -4

horizontal asymptote occurs when top does not have higher exponent than bottom
since 3x^2 is on top, not asymptote exists

anonymous · Answer

Do you know what the slanted asymptote is

dumbcow · Answer

yes its the curve as x-> infinity
in this case it equals 3x^2

dumbcow · Answer

here is graph http://www.wolframalpha.com/input/?i=plot+3x%5E2+-12%2F%28x%2B4%29

anonymous · Answer

So the slanted asymptote would be: 3x^2

dumbcow · Answer

normally slanted asymptote look like this http://www.wolframalpha.com/input/?i=plot+%283x%5E2+-12%29%2F%28x%2B4%29

dumbcow · Answer

lets make sure we are both talking about the same function

anonymous · Answer

Ok.. What would the slanted asymptote be of the first equation I posted?

dumbcow · Answer

does that match graph 1 or graph 2 ?

anonymous · Answer

Graph 1

dumbcow · Answer

ok well the graph will approach "3x^2" as x->infinity so you could call it a slant asymptote even though its not a straight line

anonymous · Answer

Cool..thx

dumbcow · Answer

yw