Question

Graph the function. Label the vertex and axis of symmetry.

y= -2(x-4)(x-2)

Answer 1

@Easyaspi314

Answer 2

we do know that x = 2 and x = 4 will be the x-intercepts because when you solve -2(x-2)(x-4) = 0, you get x = 2 and x = 4.

Answer 3

Now, y = -2(x-4)(x-2)
= -2(x^2 - 6x + 8)
= -2x^2 + 12x - 16

To find the vertex, we will compute -b/2a, that will give us the x-coordinate of the vertex.

a = -2 and b = 12, so -b/2a = -12/-4 = 3
So x = 3 is the x-coordinate. To find the y-coordinate we plug in x = 3 into the equation, and we get y = 2

So the VERTEX is at (3,2)

And, x = 3 will be the line of symmetry.

(Note, to find line of symmetry for the parabola, it is x = -b/2a).

So now we can graph this parabola.

I will try graphing it.

Answer 4

Notice that (3,2) is the vertex..notice the x-intercepts of x = 2 and x = 4.

Answer 5

Draw the vertical line x = 3, you will see it is a line of symmetyry (it is a line that cuts the parabola in half).

Does this all make sense? Understand???

Answer 6

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Answer 7

wait so the other points r 4, 2?