Question

2 tan^2x+11 tanx+9=0

plesssssss I have quizzzz

Answer 1

help me plesssssss

Answer 2

:(

Answer 3

Where are the parentheses on the equation?

Answer 4

(0,2pi)

Answer 5

replace tan(x) with x to make it easier and then you have 2x^2 +11x+9=0

Answer 6

so what is the answer im not that good on this subject

Answer 7

they need the exact value and approximate value

Answer 8

well then you can factor it into (2x+9)(x+1) and solve each portion for x, replace x with tan(x) and take the inverse tangent

Answer 9

Wilfley :( I don't know how to do it

Answer 10

2x+9=0 x=-9/2 tan(x)=-9/2 tan^-1(-9/2)=x
x+1=0 x=-1 tan(x)=-1 tan^-1(-1)=x

Answer 11

then for approximate values of x just plug in to your calculator

Answer 12

nice, now tan^-1(-1)=x this one is the exact value for x ?

Answer 13

one of them, the other is the one above it

Answer 14

choose it for me plessss :*

Answer 15

\[x=\tan^{-1} (-\frac{ 9 }{ 2 }) and x=\tan^{-1} (-1)\]

Answer 16

it should be between (0,2pi)

Answer 17

Wilfleyyyyyyyyyyyy

Answer 18

:(

Answer 19

trying to remember

Answer 20

plessssssssss

Answer 21

I think I'm missing something or just can't remember, for the -1 the exact is -pi/4 which I believe would just be moving clockwise from 0 pi/4 which would be between o and 2pi

Answer 22

-1 is 3pi/4 I think

Answer 23

I don't want to be wrong though

Answer 24

yeah, -pi/4 is 3pi/4

Answer 25

u know it more than me :(

Answer 26

just a minute and I'll check it

Answer 27

ples my life in ur hand lol

Answer 28

you have to pick 1 of them?

Answer 29

x+1=0