Question

Help please?? medals given.

Answer 1

What do you need help with?

Answer 2

finding the square root
11x^2=-5x^2-1

Answer 3

add 5x^2 on both sides first, what u get ?

Answer 4

group them

Answer 5

16x^2=-1 ?

Answer 6

like hartnn said

Answer 7

yep now you can take square root on both sides

Answer 8

so would i put 16x=i ?

Answer 9

you take the square root of 16 too, right ?
\(\Large \sqrt{16x^2}=
\sqrt {-1} \\ \Large \sqrt {16}x = \pm i\)
also don't forget the +/- sign...

Answer 10

so whats the square root of 16 ?

Answer 11

4

Answer 12

yep, so final answers for x ?

Answer 13

oh so x=4i ?

Answer 14

no...

Answer 15

note that this is a quadratic equation, degree =2
so it must have 2 root/values of x

we have 4x = +/-i
so,
4x = i or 4x = -i

so, x = i/4 or x =-i/4

got this ?

Answer 16

oh ok thanks a bunch! appreciate it!!:)

Answer 17

welcome ^_^