Question

@jim_thompson5910 give me a sec please

Answer 1

ABCD is a square with a side length of 9 units. If the ratio of CD:CE is 2:5, what is the area of ABCDE? I'll draw it below

Answer 2

how long is DE or ED

Answer 3

I'm not given that

Answer 4

you can easily figure it out though

hint: ABCD is a square

Answer 5

sorry I meant to say "ABDE is a square"

Answer 6

oh it'll be 9!

Answer 7

yes, so if CD = x, then we can set up this ratio

CD/CE = 2/5

CD/(DE+CD) = 2/5

x/(9+x) = 2/5

5x = 2(9+x)


now solve for x

Answer 8

x=6

Answer 9

@jim_thompson5910

Answer 10

good

Answer 11

now you need to find the area of the square and the area of the triangle

Answer 12

The area of the square will be 6 and I think the area of the triangle will be 15 ?

Answer 13

the area of the square is not 6

Answer 14

remember, the sides of the square are 9

Answer 15

oh no! i mean 81, my bad!

Answer 16

good, the area of the triangle is not 15

Answer 17

the base is 6, the height is 9

use that in A = b*h/2

Answer 18

54

Answer 19

now cut that in half

Answer 20

27

Answer 21

good, so the total area is: 81+27 = 108

Answer 22

the units are "square units"

Answer 23

I'm confused on how x=6 relates back to the problem

Answer 24

x = 6 is the base of the triangle

Answer 25

it's the length of CD

Answer 26

oh i taught the base was 2 bc on the problem it says CD:C3 is 2:5

Answer 27

that 2 is the ratio, it's not the actual length of CD

Answer 28

part of the ratio I should say

Answer 29

I think I have a better understanding of it now! Thank you oso much! I really mean it

Answer 30

you're welcome