Question

Trying to find the slope of a curve at a point:
y=x^2-3x-1 at x=0
the formula is lim h-->0 f(a+h)-f(a) all over h

Answer 1

where wer u stuck ?

Answer 2

I'm just kind of wondering what the answer was... I got -2 but I wanted to make sure it was right.

Answer 3

A bit of confirmation if you will

Answer 4

-2 is not correct,
looks u made some mistake in simplifying... check once :)

Answer 5

ok thank you

Answer 6

is it -1?

Answer 7

\(\large \lim \limits_{ h->0} \frac{f(a+h) - f(a)}{h}\)


\(\large \lim \limits_{ h->0} \frac{f(0+h) - f(0)}{h}\)

\(\large \lim \limits_{ h->0} \frac{f(h) - f(0)}{h}\)

\(\large \lim \limits_{ h->0} \frac{h^2-3h-1 - (0^2-3*0 -1 )}{h}\)

\(\large \lim \limits_{ h->0} \frac{h^2-3h-1 - (-1 )}{h}\)

\(\large \lim \limits_{ h->0} \frac{h^2-3h-1 +1 }{h}\)

\(\large \lim \limits_{ h->0} \frac{h^2-3h }{h}\)

Answer 8

simplify

Answer 9

-3?

Answer 10

-3 is \(\large \color{red}{\checkmark}\)

Answer 11

thank you!!!!!!!

Answer 12

np :)