Question

Someone help! Convert standard form: y=x^2-2x-3 to vertex and intercept form. Convert vertex form: y-5=-2(x+1)^2 to standard and intercept form. Convert y=(x+2)(x-3) to standard and vertex form.

Answer 1

Hmm give me a second to remember!
what math are you in?

Answer 2

Pre-calc/trig

Answer 3

haha helping someone who is more advanced in math than me!! I'm only in Geometry, but i will do my best to help you out!!! i'll do some research and help ya!!
do you think you can help me out?

Answer 4

Ok thanks! I can try. What is your question?

Answer 5

I'll post it right now!

Answer 6

Okay i think i know how to do it

Answer 7

Tell me if this makes any sense

Answer 8

standard form to vertex form.
standard Y=ax^2+bx+c
Vertex y=a(x-h)^2+k
vertex: (h,K)

y=x^2-2x-3 Going to add 3 to both sides.
y+3=x^2-2x
( )( )x^2-2x+ find C
(x )(x )x^2-2x+

Answer 9

Okay so i kinda go stuck on that part

Answer 10

When I did it I got y=1(x-2)^2 -4, but I'm not sure if that's right

Answer 11

well what did you get for your two binomials?

Answer 12

The (x-1)^2

Answer 13

Well to me that looks right. I mean, I'm not in this math class yet haha but to me when i tried to work the rest out it seemed right

Answer 14

Ok thanks!

Answer 15

no problem!