OpenStudy (anonymous):

Integrate by parts.

3 years ago
OpenStudy (anonymous):

\[\int\limits_{0}^{2\pi}t^2\sin2t dt\]

3 years ago
OpenStudy (anonymous):

\[\sin 2t = 2 \sin t \cos t\]That gives us an expression where the derivative of the thing is in the thing. Which should help!

3 years ago
OpenStudy (anonymous):

I think that's all I needed :3

3 years ago
OpenStudy (anonymous):

tyyyy

3 years ago
OpenStudy (anonymous):

I just tried it and I'm getting -2pi^2, I don't think it's correct.

3 years ago
OpenStudy (anonymous):

Nvm I did it right, I'm the best!

3 years ago