Question

What is the completely factored form of d4 - 8d2 + 16?

(d2 + 4)(d2 - 4)

(d2 - 4)(d2 - 4)

(d2 + 4)(d + 2)(d - 2)

(d + 2)(d - 2)(d + 2)(d - 2)

Answer 1

@jim_thompson5910

Answer 2

hint: let z = d^2

so that makes z^2 = d^4 after you square both sides

turning

d^4 - 8d^2 + 16

into

z^2 - 8z + 16

Answer 3

you now factor z^2 - 8z + 16 to get ________ (fill in the blank)

Answer 4

(z -4)(z-4) ????

Answer 5

very good

Answer 6

now because we made z = d^2, we just replace each copy of z with d^2 to get this final answer

(d^2 - 4)(d^2 - 4)

Answer 7

d^2 or just 2 inside the parethesis?

Answer 8

or just d*

Answer 9

It's d^2 or d squared

Answer 10

not d2 or d times 2

Answer 11

when you copy/pasted the exponent symbol didn't transfer

Answer 12

ohhhh i see i see. thankyou!

Answer 13

np