Question

What is the standard form equation of the line shown below?

Graph of a line going through negative 1, 5 and 2, 4

x + 3y = 14

5x + 3y = 14

y = negative one thirdx + fourteen thirds

y − 4 = negative one third(x − 2)

Answer 1

First find the slope!
\[\frac{y_2 - y_1}{x_2 - x_1}\]
Then you can write it in point-slope form and then mess around with it until it's in standard form.

Answer 2

You're welcome. :|

Answer 3

whats the answer

Answer 4

ikr lol ^