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Write the equation in standard form of the line through the point (4,-5) with a slope of -2/5.
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\[y-y_1=m(x-x1)\]
a point on the line (x1, y1), and the slope is m
y=mx+b -5=(-2/5)(4)+b solve for b
-5=-8/5 +b what do I do next?
@quentinloy
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so you would add 8/5 to both sides to solve for b; then you would write the equation as y=(-2/5)x-(17/5)
I thought that when y is by itself it is slope intercept form?
@quentinloy
oh, you're right. I'm sorry. so you would add (2/5)x to both sides. (2/5)x+y=(-17/5)
\[(2/5)x+y=(-17/5)\]
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