use the quadratic formula to solve the equation -4x^2-3x+2=0
using the quadratic formula amounts to inputting the values it asks ... then working the basic math what part are you stuck on?
please show work!
I think im just confused on how to actually solve the problem after i input the values
show me how you inputed the values then. then i should be able to determine how to proceed
im not sure how to type the formula on this thing this is my first time on here
ascii wirks just fine -b +- sqrt(b^2 -4ac) ------------------ 2a
ok i will try
so a = -4, b= -3 and c= 2 ? so now i put it into the equation?
yes, you would insert those values into the "formula" to find the solutions
-b +- sqrt(b^2 -4ac) ------------------ 2a -(-3) +- sqrt((-3)^2 -4(-4)(2)) -------------------------- 2(-4) 3 +- sqrt( 9 +32 ) ---------------- -8 3 +- sqrt(41) - ------------ 8
ok yah i was just typing that, so its 3/8 +-sqrt (41/8) ?
negative 3/8
-3/8 +- .... if i see it right
yeah :)
ok yes thank you so much! you made it a lot easier to understand than my teacher lol! thx!
3/8 +-sqrt (41/8) ^^ might be a typo, but make sure you dont include that 8 into the sqrt
3/8 +-sqrt (41)/8
ugh, forgot the - again
ohhh ok i see! thanks yeah sorry about that!
good luck ;)
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