help please..excluded values of 60x^3/12x ?
excluded values are the values of x that would make the denominator 0. any ideas?
@pitamar well i had 5x^2 but i was thinking that was just a simplified version...or is that the excluded value? i felt like that was wrong
Just in case, what was it in the first place? though no, I don't think it's necessarily wrong.
when finding excluded values i thought the final answer is supposed to look something like x ≠ such and such @pitamar
yes.. but for this, you have to find for what values 'x' is illegal. x value is a illegal for example, when it makes a division by 0. because then it has undefined behavior of dividing by 0.. So.. when does it happen?
so 0 is the excluded value? @pitamar
yes, because \( 12x \ne 0 \quad \implies \quad x \ne 0 \)
thanks for the help! @pitamar
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