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Of all number whose diff is 20, find the 2 that have min product.
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0 and 20?
that's what I figured.. didn't want to be wrong lol
Oh no we could use negatives too...
why would it not just be -infinity+20
-10 and 10 multiply to -100 -inf and -inf +20 multiply to a positive number
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because inifinity is not 20 spaces from 20, otherwise we would only have 40 numbers
Well more importantly, the product of two negative numbers is a positive, not the minimum required.
-10 and 10 would give the smallest product, though. A square helps to realize this (with the same perimeter, the squares area is always greater than the rectangle)
right, i can't think of a number that beats -100 either so i guess that's right.
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