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Solve for x problems. will give medal!! 3 over 4 x + 5 over 8 = 4x (x plus 16)over 3 = 3x
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\[\frac{3}{4x}+\frac{5}{8}=4x\] you can use one of your equations, both aren't necessary for one variable
No, they are two different equations
I am not sure how to solve them. They are two different ones tho. @SolomonZelman
1) Everything times 4x write out what you get from this.
its 3+2.5 when multiplied by 4
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so 3x+2.5=4x
Sorry, everything times 8x
6x+5=4x
6+5x=16x^2
how did you get the 16^2
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4x times 4x or (4x)^2 the square goes on x and the 4, so 16x^2
\[6+5x=16x^2\]
would it be 4?
the x? No! Solve it first, don't guess.
subtract 16x^2 from both sides
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