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Prove: sin θ - sin θ•cos^2 θ = sin^3 θ. You must show all work.
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\[\cos^2\theta = 1-\sin^2\theta\]
take sin theta common and then use the identity.
\[\sin \theta-\sin \theta *(1-\sin^2 \theta)\]
sin\[\sin \theta -\sin \theta +\sin^3\theta\]
=\[\sin^3 \theta\]
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