Question

Can someone please help me with this?

Part a.) Write the equation of the line that has a slope of -2 and a y-intercept of -6. (5 points)

Part b.) Write the equation of the line that passes through the point (6, -2) and has a slope of -2/3. (5 points)

Answer 1

am from pakstain .and its too tough

Answer 2

were you taught
point slope form or slope-intercept form?

Answer 3

We were are freshman year, but i'm a junior now, it's be
en a while since iv'e done this stuff.

Answer 4

for part a, you can use slope-intercept form
which is: y = mx + b when m = slope and b = y-intercept
so when the line has a slope of -2 and a y-intercept of -6,
plug m = -2 and b = -6 into the slope-intercept form.

Answer 5

So, y=-2(x)+(-6)

Answer 6

yep, that would be your first equation :)

Answer 7

now for the second equation,
you can use point-slope form, which is:
y - (y1) = m(x - (x1)) when given a point (x1, y1) and the slope = m
so when given the point (6, -2) and a slope of -2/3
plug in x1 = 6, y1 = -2 , and m = (-2/3)

Answer 8

y-2= -2/3(x-6)?

Answer 9

know that y - (-2) would be y + 2

Answer 10

Okay, I think I got it, is that all I have to do?

Answer 11

yup :)

Answer 12

Awesome! Thanks(: