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Mathematics 16 Online
OpenStudy (anonymous):

complete factoring expressions without gcf? how?

OpenStudy (anonymous):

Try x^4 - 1.

OpenStudy (anonymous):

so (x ) (x )

OpenStudy (anonymous):

in that form however i need to factor out the whole equation to the simplest form

OpenStudy (anonymous):

x^2 ***

OpenStudy (anonymous):

(x)(x) is x^2. Thats not factoring. x is not a factor of x^4 - 1.

OpenStudy (anonymous):

Oh, I am talking in forms of Trinomials, DoPs, GCF, etc. Complete Factoring is usually done with GCF and or DoPs and trinomial factoring

OpenStudy (ranga):

This identity may be useful here: \[\Large a^{2} - b^{2} = (a + b)(a - b)\]

OpenStudy (anonymous):

In this case, I want to learn how to do this w/o GCF

OpenStudy (anonymous):

That is fine thx range

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