Question

Quadrilateral OPQR is inscribed in circle N as shown below. What is the measure of ∠PQR?

Select one:
a. 41
b. 67
c. 113
d. 139

Answer 1

If a quadrilateral is inscribed in a circle, then the opposite angles of the quadrilateral are supplementary. That is the theorem needed to do this problem.

Answer 2

So, m<PQR + m<ROP = 180

(6x - 5) + (x + 17) = 180

@chantz417 Would you look on the diagram and see if I typed the angle measures correctly. I messed up on another problem (typo) so please check. After that, we have to solve for x.

Answer 3

@chantz417 ^^^^^ Do that so we can knock out this problem.

Answer 4

im working on it

Answer 5

You're doing the wrong thing.

Here is what I asked you to do:

** Would you look on the diagram and see if I typed the angle measures correctly. I messed up on another problem (typo) so please check. **

@chantz417

Answer 6

yes those are correct

Answer 7

it takes me forever to reply cause my computer is so slow

Answer 8

Now, there's this:

(6x - 5) + (x + 17) = 180

7x + 12 = 180

@chantz417 x = ?

Answer 9

>>it takes me forever to reply cause my computer is so slow

I have had that problem myself. I put FireFox on my machine and "things" got a little faster but I can already tell that the site is slow tonight. Plus, my computer is running its fan on high speed.

Answer 10

Let's get a move on this:

7x + 12 = 180

7x = 168

x = 168/7 = ? @chantz417

Answer 11

24 right

Answer 12

Yes.

Then, m<PQR = 6*24 -5 = ? @chantz417

Answer 13

139

Answer 14

Yes, that is what I got.

Answer 15

it is 67 NOT 139

Answer 16

ANSWER IS 41

Answer 17

So the answer is 41 @reed