Question

Help!

Answer 1

A rectangle is inscribed within a circle. The coordinates of the rectangle are (-8,3); (20,3); (-8,-5); and (20,-5). What is the area and circumference of the circle?

Answer 2

@dumbcow

Answer 3

@Hero

Answer 4

@Easyaspi314

Answer 5

@e.mccormick

Answer 6

find radius of circle using pythagorean thm

Answer 7

Where did you get the 14 and 4 from?

Answer 8

@Compassionate

Answer 9

from the coordinates of rectangle you know the length=28 and width = 8

Answer 10

find the distance of the rectangle's diagonal which would be the circle's diameter

Answer 11

Oh okay! Yeah I understand that part. And after that?

Answer 12

once you get the diameter
half the diameter is the radius
area of circle: pi * (radius)^2
circumference of circle: pi * diameter

Answer 13

And how can I find the diameter of this figure?

Answer 14

the diameter is the distance from point (-8,3) to point (20,-5)

Answer 15

Would I need to sorta figure out the slope to get the diameter?

Answer 16

distance formula is:
\[\sqrt{(x _{2}-x _{1})^{2}+(y _{2}-y _{1})^{2}}\]
when given the points (x1, y1) and (x2, y2)
so plug in for x2 = 20 , x1 = -8 , y2 = -5 , y1 = 3

Answer 17

Give me a min to try to solve it please

Answer 18

Is it 29.12 @jigglypuff314 ?

Answer 19

it would be best to keep it with square roots and stuff :)

Answer 20

so then it'll be like 784^2 and -8^2

Answer 21

the diameter would be √848

Answer 22

Oh okay that's what I got

Answer 23

so area would be
pi(√848)^2
= 848*pi

Answer 24

Then will that mean that the radius is 424 square root?

Answer 25

And what about the circumference?

Answer 26

@jigglypuff314

Answer 27

circumference would just be pi times diameter
so pi * √848
which can be simplified to
4pi√53 if you want

Answer 28

For the area, isn't it suppose to be the radius and not the diameter?

Answer 29

oh right, sorry, yeah so then
pi * (1/2 * √848)^2
pi * (1/2 * 2√212)^2
pi * (√212)^2
so 212pi

Answer 30

Why would you multiply by 1/2?

Answer 31

radius = 1/2 diameter

Answer 32

thanks

Answer 33

glad I could help :)