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let me writ eit
write*\[4^{x}=16\]
@ranga
\[16^{\sqrt{2}}\]
my bad
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Is the problem 4^x = 16^sqrt(2) and solve for x?
16 is a square root. The exponent is 2. 4^2=16 or 4*4=16
sprry rang yes it is
super slow net
\[\Large 4^{x} = 16^\sqrt{2}\]16 can be written as: \[\Large 4^{2}\]Therefore, \[\large 4^x = (4^{2})^{\sqrt{2}} = 4^{2\sqrt{2}}\]The base 4 is the same on both sides of the equation and therefore the exponents must be the same. So, \[\Large x = 2\sqrt{2}\]
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ok
A. 2 B. 4 C. 9/4 D. 9/8
thos eare choices tho
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