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write the canonical equation of the straight line that goes through the points A(0,3) and B(4, -4).
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find the slope \[M = \frac{ -4-3 }{ 4-0 }\] which equals -7/4
you can use the points given to find the equation of the line... using the equation (y-y1)=m(x-x1) if you use point A(0,3) your equation would look like y-3=-7/4(x-0) then use algebra to put it in whatever form you want, I like point slope form because its easy to manipulate.
would you mind telling me how will it look like in the slope form?
y=-7/4x +3
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