plse solve this
any more description to this? What is A.P. ? Any graphics with this?
no...
one
hw
@Directrix
I worked on this when you first posted it and did not get anywhere. Sorry to be of no help.
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And what is A.P. ?
@wolf1728 I think it is Arithmetic Progression. I was wondering about right triangles and Pythagorean triples such as 3,4,5 and then 15, 20, 25 and 12, 16, 20 but that led nowhere.
Arithmetic Progression and Arithmetic Sequence are the same, I think.
@experimentX
two questions on ur question :- 1) are they right triangles ? 2) and you want to solve them in integers ?
given the second post ,,, there are infinite such triangles with smallest side 20
if by that you mean right angle triangle, then your approach is correct.
you might look into 5, 12, 13
let me try.... sum of 2 sides of triangle must be > 3rd the 3 sides are 20, 20+d, 20+2d (d is positive only) so, 20 + 20 +d > 20 +2d 20 > d 20 + 20+2d >20 +d d>-20 obviously 20+2d+20+d >20 3d >-20 also obviously so, d can be less than 20 only... like if d = 1 , 20,21,22 d=2 20, 24, 26 ...... till d= 19 20, 39, 58 so there are 19 such triangles i have not assumed a right triangle
woops!! i forgot they were in AP.
but how 20 came
"If the shortest side is 20" so, 1st term = 20, and other 2 terms > 20 hence d id positive
but in question, the shortest side = 10 cm
your question "The sides of a triangle are in A.P. If the shortest side is 20, the number of such triangles are"
if its 10, then, just replace 20 by 10 there will be 9 triangles then
oops.ssrry
did you get what i have done ?
yes, i m seeing
okay , i got it , but why till d = 19 has taken
20 + 20 +d > 20 +2d 20 > d so d must be less than 20, but positive so, d= 1 to 19
okay thanks u so much , i got it
welcome ^_^
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