find the slope intercept equation for the line tangent to the curve,
y=f(x) when x=3, if f(3)=4 and f'(3)=-2

Question

find the slope intercept equation for the line tangent to the curve,
y=f(x) when x=3, if f(3)=4 and f'(3)=-2

amistre64 · Answer

they give you a point and a slope ....

amistre64 · Answer

given a point (a,b), and a slope m; a line equation can be formed as:

y = m(x-a)+b

anonymous · Answer

@amistre64 So I am confused how to figure out the slope and the m from the equation given?

amistre64 · Answer

f' IS the slope at a given point, and the point is defined for you as x=3, f(3)=4

amistre64 · Answer

given a point (a,b), and a slope m; a line equation can be formed as:
                   (3,4)            f' = -2


y =  m(x-a)+b
   = -2(x-3)+4

expand to match the slope intercept format

anonymous · Answer

thats, 
y=-2x+6+4
y=-2x+10

amistre64 · Answer

looks good to me

anonymous · Answer

@amistre64 thanks.