Question

What is f(x)/g(x) when f(x) = 6x3 - 19x2 + 16x - 4 and g(x) = x - 2?

Answer 1

What do you think it is?

Answer 2

@shamil98 I honestly have no clue.

Answer 3

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Answer 4

@shamil98 I have it set up but I dont know how to even start solving it... I have:

6x^3-19x+16x-4/x-2

Answer 5

in this case..

Answer 6

f(x) = 6x^3 - 19x^2 + 16x - 4 and g(x) = x - 2

f(2) = 6(2)^3 - 19(2)^2 + 16(2) - 4

Answer 7

solve

Answer 8

how do i solve? @Dara08

Answer 9

oh. wait

Answer 10

well you can use long division anyway

Answer 11

but

Answer 12

i used remainder theorem in this case you solve for f(2) = 6(2)^3 - 19(2)^2 + 16(2) - 4

Answer 13

the result of this 6(2)^3 - 19(2)^2 + 16(2) - 4 will be the asnwer

Answer 14

thats not one of the answer choices @Dara08

Answer 15

the answer is 312, is it therE?

Answer 16

aw, no. i'm sorry the answer is Zero

Answer 17

using synthetic division

Answer 18

I guessed and got it right! thank you though @Dara08

Answer 19

your answer is zero?