Question

I'm a little confused...someone help please?

Answer 1

hint :
product of slope of perpendicular lines = -1

Answer 2

so if one of the slope is 5 , whats the other ?

Answer 3

-5 or -5/1 or -1/5 thats what I get confused about..

Answer 4

ok, so product = -1
let other slope be 'x'
so,
\(\Large 5x =-1\)
find x from here ?

Answer 5

hint : *divide both sides by 5*

Answer 6

-0.2

Answer 7

that is -1/5 :)

Answer 8

what if it was -2/3 instead of 5?

Answer 9

\(\Large (-2/3)x=-1\)

start by canceling the negative signs from both sides and multiplying by 3

Answer 10

so it's -3?

Answer 11

no....
\(\large -2x = -3 \\ \large 2x =3 \\ \large x = \dfrac{3}{2}\)


got this ?

Answer 12

Oh alright! Thank you!

Answer 13

welcome ^_^