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Given a triangle with b = 7 c = 3 and A = 37 degrees, what is the length of a?
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sounds like a job for the law of cosines... http://www.mathsisfun.com/algebra/trig-cosine-law.html
I did that, but I keep getting an answer that isn't an answer choice
what did you get?
6.5
okay, just a sec...
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|dw:1383164187516:dw| \[a^2=b^2+c^2-2bc \cos A= 7^2+3^2-2(7)(3)\cos 37^{\circ}=49+9-42(.7986355...)\] \[=24.457308...\Rightarrow a=\sqrt{a^2}=\sqrt{24.457308...}=4.945433103...\]
did you find your mistake?
Yeah I did. Thank you so much
you're welcome!
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