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The graph of which equation is shown below?
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y = −x^2 + 2x − 3 y = −x^2 − 2x − 3 y = x^2 + 2x − 3 y = x^2 − 2x − 3
hint:the zeros of these functions are 1 and -3
so it would be the second one?
if plugging in x = -3 and 1 give 0 then yes
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The parabola opens upwards. So the coefficient of x^2 has to be positive. Quickly you can rule out two choices.
right
i can rule out A and B
yes - now try the substitutions
does this go with the formula y=mx+b?
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oh no it doesnt that finding slope intercept
ok the answer is x^2 +2x -3
f(1) for 3rd option is (1)^2 + 2(1) - 3 = 0 f(-3) = ?
correct
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